That is a very simple mathematics question.
# c |( ^2 f1 \Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。 |& G, M! Z1 ]( K0 n
6x + 3y + z/2 = 100 Formula 14 U, C" O: x4 i* g( \, L4 T2 X$ {
x + y + z = 100 Formula 2+ Y; p) h, C) ?" y1 N8 i
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) V5 ]# [, g* q, j _# Y& Z/ n
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvboxnow.com+ o. v/ E! W! i6 P% t1 I
Formula 4 can change into 11x + 5y = 100 Formula 5. Z7 X& h+ M- }' V3 H- x1 n
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
a" A4 x) w, NTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80., O9 [0 P8 u* u: A7 t
Eventually, the answer is 20 female and 80 children and no male. |