That is a very simple mathematics question.
" A% d" w" [1 L$ Z; y5 A1 p" ULet x = Male, y = Female, z = Child
& v7 g6 C1 [+ f3 Z. b0 A: a6x + 3y + z/2 = 100 Formula 1) n! J7 \) W- v( [
x + y + z = 100 Formula 28 H2 o+ ^) K0 d- S# F6 _: v
Simplify Formula 2 into z, we get z = 100 - x - y Formula 32 n! v/ m7 }9 v+ m! w; ^3 i5 r
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
! c2 F0 M4 Q5 {) I& K. nTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5/ O" Z4 o1 s1 s+ v9 b& p
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
5 t1 d- C% Y% B7 H+ F2 `' ~1 }TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvboxnow.com7 ]: `3 u# b1 k, C; z" W# O
Eventually, the answer is 20 female and 80 children and no male. |