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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
, [' U! T- T+ G5 Dtvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)公仔箱論壇  I( a! f5 ]3 i7 [
then 称 them c which side is the heavy
: r% m+ f3 `# w* @) b. b/ Kthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ }# S2 g! t8 k2 a- Z# \
if not balance take the heavy and then 公仔箱論壇3 f* ~, o; N1 C$ O; y1 B
take the heavy group divided into 2 group i group contain 1 ball than 称 it
" C& z! [5 K) p6 t8 Q, xtvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
/ U$ n3 g3 v( g7 `(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
' z# R5 f$ z# M- D2 ]公仔箱論壇然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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