hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^% O! |+ L. \+ K/ |
1st u divide the ball into two group (i group 6 ball)
% c, V7 C$ F4 @/ jtvboxnow.comthen 称 them c which side is the heavy 公仔箱論壇3 ?% d  x  S3 N) ?4 R
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
1 V4 D7 c2 ^8 x. Rtvboxnow.comif not balance take the heavy and then
$ D% r$ \1 f' `4 C9 T' wtvboxnow.comtake the heavy group divided into 2 group i group contain 1 ball than 称 it tvboxnow.com9 M$ S" M# d/ j) v! |; A( `; j$ Q
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 3 d7 C6 \! ~4 H! n% m# C
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边公仔箱論壇9 J7 ?& f# I0 ~' d+ R
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me