hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
6 ?. j5 f$ R# s$ f# C1st u divide the ball into two group (i group 6 ball)
$ G5 X9 Q3 ]1 s$ t  E, ]: Xthen 称 them c which side is the heavy
1 \: w/ c0 v  {; h3 Gthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb0 [1 l2 ]8 a, S+ j: b2 ?
if not balance take the heavy and then
$ S( y, x6 X2 Y& b  m& C0 W  }tvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it
. b' E. C% P5 P( `, W9 G, m) etvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
8 r  m0 [' T6 N4 O* |公仔箱論壇（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边tvb now,tvbnow,bttvb  V1 [1 o" c5 x# U8 l4 v
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me