hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^tvboxnow.com7 Y8 A+ x4 N5 T" s, I
1st u divide the ball into two group (i group 6 ball)
4 }: r9 U! ]5 Q" N' R$ q3 ]4 Utvb now,tvbnow,bttvbthen 称 them c which side is the heavy
# }" r/ C  e, Z* ?) |7 [then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
% t( G: X$ s2 ~9 Z( p& i" Hif not balance take the heavy and then 5 H+ T; c; o/ l9 P4 D! M+ O% q
take the heavy group divided into 2 group i group contain 1 ball than 称 it : e% e1 a/ I! a: ^( e3 M/ J
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
; e; z! y+ e  s+ utvboxnow.com（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
* R1 G3 a  _' ^" `3 C% w) Btvboxnow.com然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me