hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^: @0 v8 k. O, P3 H8 \  v
1st u divide the ball into two group (i group 6 ball)tvboxnow.com- K, s9 N" Q4 J, z9 v$ |. c+ |# \9 H
then 称 them c which side is the heavy ) j! K2 o& U$ d) c1 j; Q' X
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
1 j% b( e: p0 k, j# K: v$ W( xif not balance take the heavy and then
! @: F* `2 z" G  E& Xtvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it ) S7 X& U/ M; ^6 ^
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: + k9 A/ Y, N* C4 }, D5 K
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边' ^" @7 l! I- w
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me