hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^公仔箱論壇' O4 F5 |1 M. K, q
1st u divide the ball into two group (i group 6 ball)
8 |! j3 ~9 H* J+ E$ U, Dtvboxnow.comthen 称 them c which side is the heavy
" H" A- y. ?0 R! d. F& Zthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
# m: {" }# E! {6 {, ?& w9 k* B  Kif not balance take the heavy and then
/ F- E! N' {1 x- Q; G  J+ d公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it + Y+ [# H; Y- `, |9 G6 x4 V
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
9 G/ [2 y0 ]" n; I& b+ |（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边tvboxnow.com/ V8 y6 p9 R/ h; C" x7 z
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me