hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^7 u0 e$ U. l7 j9 s0 l" I# x
1st u divide the ball into two group (i group 6 ball)
, M3 K# R6 b% D! R" c6 otvboxnow.comthen 称 them c which side is the heavy TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。/ z  A) @6 q  y$ g) Z
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 公仔箱論壇$ ]' {! W5 L$ v; H0 Z
if not balance take the heavy and then
( O) g( z' e9 F+ j: Y公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it tvboxnow.com3 e3 C; o, ^6 h6 q2 r  i4 L' `9 }9 h
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
$ v8 G, Q4 |  m! {7 k# \8 q* y+ E（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
# e5 V$ O) w! \* X然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me