返回列表 回復 發帖
see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
+ o3 h" i7 V6 l( ^0 d将比较重的那份再平均分成两份成一次' v# C. o+ E: U! u
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
: C* I3 D. M5 |! Y% eif  (4v4)= same that means the rest of 4 is got more weight
! M$ l3 E" b6 W! rtvb now,tvbnow,bttvb    then goto 2 - compare rest of(4)  - 2 with 2
# D4 a8 q1 o+ Z5 `% U2 H! _+ U* g2 Htvboxnow.com           if (left side is more weight)
2 J# D8 V2 ]4 R- g2 X: Utvb now,tvbnow,bttvb              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
* Q8 R2 R5 S3 v) A5 ~1 P          else ( right side is more weight)
& _' u0 w% J, o- k              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer3 J4 _4 k! G: C
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
返回列表