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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次公仔箱論壇6 Q' U+ i4 c( o% `+ ?
将比较重的那份再平均分成两份成一次. K7 j7 t. C, \" j& s
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4tvboxnow.com3 V$ y9 z; }) ?6 W' k- \; F
if  (4v4)= same that means the rest of 4 is got more weight
9 {7 {4 l% W4 c2 Y( L# }0 ]& }  g2 ]tvb now,tvbnow,bttvb    then goto 2 - compare rest of(4)  - 2 with 2
3 i- o3 H0 i' s( n4 ~9 S           if (left side is more weight)
- Y% I* d: }6 _# _% i! _5 V              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
9 g! r& a. w, a6 Ltvb now,tvbnow,bttvb          else ( right side is more weight): e# j7 E4 P" s
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
, f/ a8 h( l0 C% S- a9 a, Delse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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