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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次公仔箱論壇7 P; u4 R! M* d7 \# f. B& l# ~% {
将比较重的那份再平均分成两份成一次5 C! ^+ c( d5 b) v% q
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
% _; d, H6 G- M$ t1 Aif  (4v4)= same that means the rest of 4 is got more weight7 U, [) v: b; i5 L
    then goto 2 - compare rest of(4)  - 2 with 2 公仔箱論壇9 [* V9 n, |/ a! N
           if (left side is more weight)tvb now,tvbnow,bttvb- \2 @4 U6 x8 T
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer公仔箱論壇' d7 `/ G( r% a6 @- J+ I
          else ( right side is more weight)tvb now,tvbnow,bttvb( u1 H5 J# k* V
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer公仔箱論壇( }+ j% B4 Q. ]) Z1 y/ B3 H
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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