zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次; J. _4 b  T* k& t
将比较重的那份再平均分成两份成一次( z# a- l' L* C0 {) B
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
* A" B" l, z' \/ ?. l2 o! ttvb now,tvbnow,bttvbif  (4v4)= same that means the rest of 4 is got more weight
' U: h, l( ~, K! J0 }. I7 C  c公仔箱論壇    then goto 2 - compare rest of(4)  - 2 with 2 tvb now,tvbnow,bttvb! u/ u! j0 D% @: R" N
           if (left side is more weight)+ ~! [+ W: @% W$ a
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
# F7 w* c% ]0 F2 k公仔箱論壇          else ( right side is more weight)
+ V9 m: m: u6 ]8 h; ~! t              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer& p6 u" g& H1 {; y7 `3 p/ y
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。