zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
2 x: l/ J( M- Q5 P公仔箱論壇将比较重的那份再平均分成两份成一次TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。. ?* Z, n) B' U- c: L9 Q
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
5 ^% d! F7 u& ~6 c% Kif  (4v4)= same that means the rest of 4 is got more weight
2 z# |' T% Z9 H! T8 Q, L. h; |tvb now,tvbnow,bttvb    then goto 2 - compare rest of(4)  - 2 with 2 tvb now,tvbnow,bttvb; ~$ A9 O. W/ \9 T4 j3 G7 t
           if (left side is more weight)1 I- G- H! a( O& a0 f
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
; p- f8 J1 I9 P2 Utvboxnow.com          else ( right side is more weight)
5 R* x! {" p. W$ b4 w4 _公仔箱論壇              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer2 y# K" G. k/ r+ b' Q) C9 t4 z
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。