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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvboxnow.com6 D/ d( F% d, ?/ T/ x8 {
共四堆' c: T+ a/ y/ P: i( T) i
称两次得出异常的在那一堆,其轻重3 _* u/ F  D1 e7 w/ @0 k
在异常的那一堆中在称一次
- i2 |$ Q8 T0 l( Ftvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4. tvboxnow.com+ T/ P. C9 K* f) b
weight any 2 sets.
& X% g# M/ a: P6 S/ z$ l0 D% w3 ?if the 2 sets are equal, then you know the heavy one is in the third5 u, f' f" ~& v
if one of the 2 is heavier, then the heavy one is in that set
0 ^( F! W- u( w+ ^then divide the 4 balls into 2.
& f  J- |$ ^5 G# ^* M$ Z3 htvboxnow.comweigh them
# N0 S- s2 N- b, f) E- [  Ctvboxnow.comand divide the heavier into 1
* S. s5 f9 A# J' p7 @, ?/ J3 Y9 ytvboxnow.comand weight them.
$ g( X# q7 R6 T$ Htvboxnow.com3 x weighing and get the ans.  tvboxnow.com; Y# y7 G0 Y4 X+ B- |" L% D$ i! M
in less than 15 secs.
1. 6 aside and weight.
6 I+ S- X+ j) B, z) o/ S! D6 `tvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.1 B! S! [& k/ H4 [8 `% u
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
! k4 q: P0 y* h. ^9 [( Q7 f! u+ jtvboxnow.comTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。/ i. Q* e- ?" z" F& N
but i have a question. 重量異常 can be heavier or lighter.... so......
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