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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
6 R0 i* I& V7 i2 Q7 l# x7 Otvb now,tvbnow,bttvb共四堆
2 v, d: S6 t' `+ k称两次得出异常的在那一堆,其轻重公仔箱論壇% f3 m+ h+ X" G( {
在异常的那一堆中在称一次) `  V( u( B- B/ E
就可以找到了
divde the 12 balls into 3 sets of 4.
, z- @& l/ v- o5 W! P( D& U% Tweight any 2 sets.tvboxnow.com. o7 n4 M0 C, [
if the 2 sets are equal, then you know the heavy one is in the thirdtvboxnow.com1 ]3 B# D4 p# ^( m* G  F
if one of the 2 is heavier, then the heavy one is in that set/ b" z3 v* I# Q3 d
then divide the 4 balls into 2.
: D- F$ }& a+ F$ i2 W0 d  w6 nweigh them
# A7 _, c$ G% x% f/ ~tvboxnow.comand divide the heavier into 1
; r0 V6 }# n* C0 m/ o+ Btvboxnow.comand weight them.
4 q; z3 s( H7 E. `TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 x weighing and get the ans.  $ h) S8 ~& Z* V# A7 S- _+ @
in less than 15 secs.
1. 6 aside and weight.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。  n# K2 [$ c! G* [) I
2. heavier side from (1), 3 aside weight again.
2 H% V9 F. A3 X) `" u  I3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
# X/ T: ]7 N  H9 X/ G3 FTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。
, j+ T5 ]2 F) z' k6 f. _- L3 m0 LTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。but i have a question. 重量異常 can be heavier or lighter.... so......
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