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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
! y# a. L% T9 Q' v% |tvb now,tvbnow,bttvb共四堆! r9 q2 m' S/ H
称两次得出异常的在那一堆,其轻重
6 D9 t' X; z2 |在异常的那一堆中在称一次
/ W* M- K- G0 d7 |+ V4 @8 ?0 `2 S) Mtvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4. 公仔箱論壇' h9 \; _3 H7 w& r! `! w
weight any 2 sets.
- R3 R0 Q* e- L公仔箱論壇if the 2 sets are equal, then you know the heavy one is in the third
/ t# A( l% R' G$ w9 A( D1 _公仔箱論壇if one of the 2 is heavier, then the heavy one is in that set
# z3 Q3 ^/ T9 }1 W  V5 Ltvboxnow.comthen divide the 4 balls into 2.
: a) ~5 S3 I/ _weigh them
3 F% a3 @  J; k/ L1 m: ?7 r* [: K8 gtvboxnow.comand divide the heavier into 1tvboxnow.com0 n1 ^$ `; `8 S. k% E
and weight them.# \7 S0 |0 w1 f- ], G
3 x weighing and get the ans.  
  _7 M' o5 @( P$ M7 l3 P7 m" C4 L) Hin less than 15 secs.
1. 6 aside and weight.3 u2 ?  I- P( [5 Q3 F1 F
2. heavier side from (1), 3 aside weight again.# a  E- w( s$ u1 ~4 m5 }
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
1 k# I% r6 E9 t. Q; b" \1 |9 \% Jtvb now,tvbnow,bttvb
) W7 B$ b- y0 W$ `6 V- L; G+ w" T! Nbut i have a question. 重量異常 can be heavier or lighter.... so......
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