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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
" t4 `* }* [; e5 _共四堆tvboxnow.com5 V, R+ B; d" @  f9 ?/ O* F3 _
称两次得出异常的在那一堆,其轻重tvboxnow.com: b6 `3 {3 L& a' W  i1 g% s+ U
在异常的那一堆中在称一次, w) E7 ^" @5 \) t7 K
就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb( ^3 f$ Q9 B: a1 E4 s
weight any 2 sets.
+ E5 J; Z: @1 b2 W8 Y' ]tvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third
2 c) @. P: P; ]  Xif one of the 2 is heavier, then the heavy one is in that set
9 E: G6 ?, k5 g$ p, T( Othen divide the 4 balls into 2.
, ^1 P) `% R, q! F! O: `公仔箱論壇weigh themTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。* o8 H; A8 I# Z6 \
and divide the heavier into 1
5 i9 U/ M% N% N6 ]  mand weight them.* f$ K2 f2 L  _# E/ z7 a
3 x weighing and get the ans.  
, M1 O, ^9 w  ztvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.3 }7 f9 \4 [. h3 E, @' V% ?# H9 }
2. heavier side from (1), 3 aside weight again.
/ l5 D8 q0 Z, Z! t/ G3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. : Q  N6 X0 g+ f( s! R2 H# h
TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) T8 l7 x7 Y3 I3 A2 K- o
but i have a question. 重量異常 can be heavier or lighter.... so......
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