put six on each side first
6 t& W6 C% m( _1 s) D公仔箱論壇/ S* r/ P0 n7 T# X! Z+ j3 E
from the heavier six, split it to three on each side
$ m- c8 [1 b8 t$ Y+ H5 L
* t$ W; r3 U* L( Xthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |