put six on each side first
, |- z9 H5 g' ^& ^/ L5 k/ vtvb now,tvbnow,bttvb) P2 u- v; Z7 ?! e' T
from the heavier six, split it to three on each side
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$ h7 e, e5 g9 L$ E5 ltvb now,tvbnow,bttvbthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |