The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.' ~" U& P; s& i0 J7 t
* V: q2 g* o# `4 E6 l6 N' \tvb now,tvbnow,bttvbStarting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.
" @9 b3 F: r! k( xtvb now,tvbnow,bttvbTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。! k4 N; e: p I
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
+ s" W3 d8 F" ^% U/ c5 qtvb now,tvbnow,bttvb
m: i# x: @5 W' xtvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20; q& ]% B' e. a
tvboxnow.com' D" R+ U% l+ s; D* B! y
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。* Y5 |" R0 z2 X7 I' w/ N
/ n2 k0 H# \; j$ ]公仔箱論壇#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
1 P! Q' S7 H# H: U" ~tvb now,tvbnow,bttvb" q6 i% A! `6 m
Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。5 X& x1 ^7 f+ ?% C; q! ?
