number 4 has the best chance to live
U0 z3 u T( q' v( r Vtvboxnow.comassume number 1, 2, 3 and 4, pick number a, b, c and d.
: Z- N: q8 b+ v$ s2 V& V; Atvboxnow.comnumber 4 knows how many left in the bag which is 100-a-b-c4 M6 K) P$ K5 j6 ?) R# d- d0 A
take the average of (100-a-b-c)
7 d+ T. L: q' V5 U5 ?公仔箱論壇then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
5 Y, V0 o8 e* F' I8 n: ~$ z公仔箱論壇and number 4 can squeeze himself into the average and what number 5 picks.公仔箱論壇* O2 E8 V' [6 ?0 ]0 J0 N( _) K
so number 4 will have the best chance.
5 N. ^" j5 P& B9 i0 N" N5 @tvboxnow.com
& i4 f* n# r( u公仔箱論壇i hope this is a good logic hehe |