loveallcar

number 4 has the best chance to live1 E1 X  @/ u5 v8 ~5 |' r$ G
assume number 1, 2, 3 and 4, pick number a, b, c and d.
; O% d8 i3 d5 {( Stvboxnow.comnumber 4 knows how many left in the bag which is 100-a-b-ctvboxnow.com. f4 K- C6 \5 N6 C
take the average of (100-a-b-c)
& Z# }- P6 m; {& _, z公仔箱論壇then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
; F* A  Q6 R. X7 x9 W; N& ctvb now,tvbnow,bttvband number 4 can squeeze himself into the average and what number 5 picks.2 `' g0 k. t3 v
so number 4 will have the best chance.9 ]& U8 A" U* H0 i% c% U- w( P3 q1 I
公仔箱論壇9 Z  k3 l  C/ H1 ^9 i
i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.
2 A! H9 F! W! u0 l# ~- }0 v# Bplease post answer latvboxnow.com! }* ?6 X* I8 [9 j$ K0 T
can't wait la