number 4 has the best chance to live公仔箱論壇8 ? l3 f4 D% O. @( b" d
assume number 1, 2, 3 and 4, pick number a, b, c and d.tvboxnow.com( z4 V9 K1 i& i$ m$ q: L2 ?
number 4 knows how many left in the bag which is 100-a-b-c
' \7 r0 z4 q4 D' o: N% q4 \& Ptake the average of (100-a-b-c)公仔箱論壇+ b* D; }; K) \! K
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
4 M3 |7 b7 T/ Rtvb now,tvbnow,bttvband number 4 can squeeze himself into the average and what number 5 picks.
( N$ t0 v' c# w& Z3 V7 ~" o, n$ Sso number 4 will have the best chance.
8 j. `4 x3 b! P4 I! O0 X; {- A% Otvb now,tvbnow,bttvb! _0 C! X& W5 W, W/ W
i hope this is a good logic hehe |