hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^公仔箱論壇5 {2 R6 n' @7 R: o' Z, n" E
1st u divide the ball into two group (i group 6 ball)公仔箱論壇) k) j9 _. b' g: C# s
then 称 them c which side is the heavy 7 c+ E# c0 G; T1 M0 M
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb5 d3 I5 G& z, [% G# ^  A4 f8 X
if not balance take the heavy and then
9 B4 f4 y  t$ O2 c; {; Ttvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it
, o: b" z  H% R. D* S; q* s+ Y3 Wthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb5 d6 R# @' T: n/ {& D; `+ b
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
' v* C/ [3 E  Ttvb now,tvbnow,bttvb然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me