The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
6 ^ o5 y- q! @0 D. O' W
* c9 U7 X1 ]5 ~. _. ]公仔箱論壇Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. tvb now,tvbnow,bttvb& K* M0 U, \$ n" K0 u$ N( c
tvb now,tvbnow,bttvb. ], h* e2 C/ p2 E% m* P
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
' E% K/ T8 \( M; @0 I4 B公仔箱論壇公仔箱論壇/ S& Y3 ~* W% M: \8 F
#3 did the obvious choice 40 divided by 2 =20, so he picked 205 D, a2 j) `) [% o' X. l% o+ f% i
tvboxnow.com. P0 G( k/ r$ a9 i- |* z4 J
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.tvb now,tvbnow,bttvb) }" f- ^3 [4 ^$ m
TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。; o" m- X7 I7 y
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。3 V' q% G, U7 |0 r; U: f' a4 r
tvb now,tvbnow,bttvb+ s' b' j" N. B s Y0 H8 {
Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
