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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次5 @1 t' ~: T7 r1 N2 ?
将比较重的那份再平均分成两份成一次
: l' W& v6 j( W. h  j  g公仔箱論壇剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4tvboxnow.com0 ^6 C3 b5 {9 i9 X
if  (4v4)= same that means the rest of 4 is got more weight
: }  G, R+ p, c2 G, p9 utvb now,tvbnow,bttvb    then goto 2 - compare rest of(4)  - 2 with 2 公仔箱論壇' T2 b0 t6 B' j9 S; Q$ D) ^9 j1 y& p
           if (left side is more weight)
6 N, R8 u1 G/ H& b) ptvb now,tvbnow,bttvb              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
/ m% l; o6 D( A) ?( {          else ( right side is more weight)
6 j" ~+ X/ R7 b, }5 `) R1 a# s6 Ftvb now,tvbnow,bttvb              then goto 3 - compare last (right side of (2) - 1 with 1 => get answertvboxnow.com+ [% o3 K9 `) H: }
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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